Question 505: AC fundamentals

Question

A $$50 \mathrm{~Hz}$$ $$\mathrm{AC}$$ signal is applied in a circuit of inductance of $$(1 / \pi) \mathrm{H}$$ and resistance $$2100 \Omega$$. The impedance offered by the circuit is

Accepted Answer

$$\begin{gathered}
	ext { Impedance } Z=\sqrt{R^2+X_L^2} \
X_L=\omega L=2 \pi f L
\end{gathered}$$
$$\begin{aligned}
	ext{Given,} \quad R & =2100 \Omega, f=50 \mathrm{~Hz}, L=\frac{1}{\pi} \
Z & =\sqrt{(2100)^2+(2 	imes 50)^2} \
& =\sqrt{(2100)^2+(100)^2} \
Z & =2102 \Omega
\end{aligned}$$

Answer

$$1500 \Omega$$

Answer

$$1700 \Omega$$

Answer

$$2102 \Omega$$

Answer

$$2500 \Omega$$

AC fundamentals

A $50 \mathrm{~Hz} \mathrm{AC} signal is applied in a circuit of inductance of (1 / \pi) \mathrm{H} and resistance 2100 \Omega$. The impedance offered by the circuit is

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