Question 409: AC fundamentals

Question

A capacitor of capacity '$$C$$' is charged to a potential '$$V$$'. It is connected in parallel to an inductor of inductance '$$\mathrm{L}$$'. The maximum current that will flow in the circuit is

Accepted Answer

The charge oscillates according to the equation
$$\begin{aligned}
& q=q_0 \cos \omega t \
& i=-\frac{d q}{d t}=\omega q_0 \sin \omega t=i_0 \sin \omega t
\end{aligned}$$
where $$i_0=\omega q_0, \omega=\frac{1}{\sqrt{\mathrm{LC}}}, q_0=C V$$
$$	herefore \quad i_0=\frac{1}{\sqrt{\mathrm{LC}}} \cdot \mathrm{CV}=\mathrm{V} \sqrt{\frac{\mathrm{C}}{\mathrm{L}}}$$

Answer

$$V \sqrt{\frac{L}{C}}$$

Answer

$$\mathrm{V} \sqrt{\mathrm{LC}}$$

Answer

$$V \sqrt{\frac{C}{L}}$$

Answer

$$\frac{\mathrm{VC}^2}{\mathrm{~L}}$$

AC fundamentals

A capacitor of capacity '$C' is charged to a potential 'V'. It is connected in parallel to an inductor of inductance '\mathrm{L}$'. The maximum current that will flow in the circuit is

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