Question 403: AC fundamentals

Question

The peak value of an alternating emf '$$\mathrm{e}$$' given by $$\mathrm{e}=\mathrm{e}_0 \cos \omega \mathrm{t}$$ is 10 volt and its frequency is $$50 \mathrm{~Hz}$$. At time $$\mathrm{t}=\frac{1}{600} \mathrm{~s}$$, the instantaneous e.m.f is $$\left(\cos \frac{\pi}{6}=\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}\right)$$

Accepted Answer

$$\begin{aligned}
& e=e_0 \cos \omega t=10 \cos 2 \pi \mathrm{ft} \
& f=50 \mathrm{~Hz}, \quad t=\frac{1}{600} s \
& \begin{aligned}
	herefore \quad=10 \cos 100 \pi 	imes \frac{1}{600}=10 \cos \frac{\pi}{6} \
\quad=10 \frac{\sqrt{3}}{2}=5 \sqrt{3} V
\end{aligned}
\end{aligned}$$

Answer

$$10 \mathrm{~V}$$

Answer

$$\frac{1}{\sqrt{3}} \mathrm{~V}$$

Answer

$$5 \mathrm{~V}$$

Answer

$$5 \sqrt{3} \mathrm{~V}$$

AC fundamentals

The peak value of an alternating emf '$\mathrm{e}' given by \mathrm{e}=\mathrm{e}_0 \cos \omega \mathrm{t} is 10 volt and its frequency is 50 \mathrm{~Hz}. At time \mathrm{t}=\frac{1}{600} \mathrm{~s}, the instantaneous e.m.f is \left(\cos \frac{\pi}{6}=\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}\right)

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