Question 384: AC fundamentals

Question

In the circuit shown the ratio of quality factor and the bandwidth is

Accepted Answer

$$\begin{aligned}
& 	ext { Bandwidth }=2 \Delta \omega=\frac{\mathrm{R}}{\mathrm{L}} \
& \mathrm{Q} 	ext { factor }=\frac{1}{\mathrm{R}} \sqrt{\frac{\mathrm{L}}{\mathrm{C}}} \
& \frac{\mathrm{Q} 	ext { factor }}{	ext { Band width }}=\frac{\frac{1}{\mathrm{R}} \sqrt{\frac{\mathrm{L}}{\mathrm{C}}}}{\frac{\mathrm{R}}{\mathrm{L}}}=\frac{1}{\mathrm{R}^2} \frac{\mathrm{L}^{3 / 2}}{\sqrt{\mathrm{C}}} \
& \frac{\mathrm{Q}_{	ext {factor }}}{	ext { Bandwidth }}=\frac{3 \sqrt{3}}{100 \sqrt{27 	imes 10^{-6}}}=\frac{3 \sqrt{3}}{100 	imes 3 \sqrt{3} 	imes 10^{-3}}=10 \mathrm{~s}
\end{aligned}$$

Answer

10 s

Answer

8 s

Answer

6 s

Answer

4 s

AC fundamentals

In the circuit shown the ratio of quality factor and the bandwidth is

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