Question 358: AC fundamentals

Question

An alternating voltage is applied to a series LCR circuit. If the current leads the voltage by $$45^{\circ}$$, then $$\left(	an 45^{\circ}=1ight)$$

Accepted Answer

The phase between the voltage and the current is given as
$$\begin{array}{ll} 
& 	an \phi=\frac{X_L-X_C}{R} \
	herefore \quad & 	an 45^{\circ}=\frac{X_L-X_C}{R} \
	herefore \quad & 1=\frac{X_L-X_C}{R} \
	herefore \quad & R=X_L-X_C \
	herefore \quad & X_L=X_C+R
\end{array}$$

Answer

$$\mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}}-\mathrm{R}$$

Answer

$$\mathrm{X}_{\mathrm{L}}=\mathrm{X}_{\mathrm{C}}+\mathrm{R}$$

Answer

$$\mathrm{X}_{\mathrm{C}}=\sqrt{\mathrm{X}_{\mathrm{L}}^2+\mathrm{R}^2}$$

Answer

$$\mathrm{X}_{\mathrm{L}}=\sqrt{\mathrm{X}_{\mathrm{C}}^2+\mathrm{R}^2}$$

AC fundamentals

An alternating voltage is applied to a series LCR circuit. If the current leads the voltage by $45^{\circ}, then \left(\tan 45^{\circ}=1\right)

Choose the correct answer: