Question 423: AC fundamentals

Question

An alternating voltge is represented by $$\mathrm{V}=80 \sin (100 \pi \mathrm{t}) \cos (100 \pi \mathrm{t})$$ volt. The peak voltage is

Accepted Answer

$$\begin{aligned}
& \sin 2 	heta=2 \sin 	heta \cdot \cos 	heta \
& \begin{aligned}
& 	herefore \quad \sin 	heta \cos 	heta=\frac{\sin 2 	heta}{2} \
& \mathrm{~V}=80 \sin (100 \pi \mathrm{t}) \cos (100 \pi \mathrm{t}) \
&=\frac{80 \sin 200 \pi \mathrm{t}}{2}=40 \sin 200 \pi \mathrm{t}
\end{aligned}
\end{aligned}$$
Amplitude or the peak value of the voltage $$=40 \mathrm{~V}$$

Answer

$$20 \mathrm{~V}$$

Answer

$$40 \mathrm{~V}$$

Answer

$$30 \mathrm{~V}$$

Answer

$$50 \mathrm{~V}$$

AC fundamentals

An alternating voltge is represented by $\mathrm{V}=80 \sin (100 \pi \mathrm{t}) \cos (100 \pi \mathrm{t})$ volt. The peak voltage is

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