Question 375: AC fundamentals

Question

In a series LCR circuit, $$\mathrm{C}=2 \mu \mathrm{F}, \mathrm{L}=1 \mathrm{mH}$$ and $$\mathrm{R}=10 \Omega$$. The ratio of the energies stored in the inductor and the capacitor, when the maximum current flows in the circuit, is

Accepted Answer

In resonance condition (current is maximum),
$$	herefore \quad \mathrm{X}_{\mathrm{C}}=\mathrm{X}_{\mathrm{L}}$$
$$	herefore$$ The ratio of energies in the inductor and capacitor is:
$$\begin{aligned}
& \frac{\mathrm{U}_{\mathrm{L}}}{\mathrm{U}_{\mathrm{C}}}=\frac{\mathrm{LI}^2}{\mathrm{CV}^2}=\frac{\mathrm{L}}{\mathrm{CR}^2} \quad \ldots .\left(\because \frac{\mathrm{I}}{\mathrm{V}}=\frac{1}{\mathrm{R}}ight) \
& \frac{\mathrm{U}_{\mathrm{L}}}{\mathrm{U}_{\mathrm{C}}}=\frac{10^{-3}}{2 	imes 10^{-6} 	imes 10^2} \
& \frac{\mathrm{U}_{\mathrm{L}}}{\mathrm{U}_{\mathrm{C}}}=\frac{5}{1}
\end{aligned}$$

Answer

$$5: 1$$

Answer

$$3: 2$$

Answer

$$1: 2$$

Answer

$$1: 5$$

AC fundamentals

In a series LCR circuit, $\mathrm{C}=2 \mu \mathrm{F}, \mathrm{L}=1 \mathrm{mH} and \mathrm{R}=10 \Omega$. The ratio of the energies stored in the inductor and the capacitor, when the maximum current flows in the circuit, is

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