Question 415: AC fundamentals

Question

In an a.c. circuit, a resistance R = 40 $$\Omega$$ and an inductance 'L' are connected in series. If the phase angle between voltage and current is 45$$^\circ$$, then the value of the inductive reactance is (tan 45$$^\circ$$ = 1)

Accepted Answer

In an AC circuit where a resistance $ R = 40 \ \Omega $ and an inductance $ L $ are connected in series, the phase angle $ \phi $ between the voltage and current is given as 45$$^\circ$$. We need to determine the inductive reactance $ X_L $.
The phase angle in an RL series circuit is given by the tangent of the angle:
$$ 	an(\phi) = \frac{X_L}{R} $$
Given $ \phi = 45^\circ $ and $ 	an 45^\circ = 1 $, we have:
$$ 	an(45^\circ) = \frac{X_L}{R} = 1 $$
Thus:
$$ X_L = R $$
Given $ R = 40 \ \Omega $, we find:
$$ X_L = 40 \ \Omega $$
Therefore, the value of the inductive reactance is 40$$\Omega$$ (Option B).

Answer

50$$\Omega$$

Answer

40$$\Omega$$

Answer

10$$\Omega$$

Answer

20$$\Omega$$

AC fundamentals

In an a.c. circuit, a resistance R = 40 $\Omega and an inductance 'L' are connected in series. If the phase angle between voltage and current is 45^\circ, then the value of the inductive reactance is (tan 45^\circ$ = 1)

Choose the correct answer: