Question 332: AC fundamentals

Question

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

Accepted Answer

Impedance for L-R circuit,
$$\mathrm{Z}_1=\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}$$
Impedance for $\mathrm{L}-\mathrm{C}-\mathrm{R}$ circuit,
$$\begin{aligned}
\quad \mathrm{Z}_2 & =\sqrt{\mathrm{R}^2+\left(\mathrm{X}_{\mathrm{L}}-\mathrm{X}_{\mathrm{c}}ight)^2} \
	herefore \quad \mathrm{Z}_2 & <\mathrm{Z}_1
\end{aligned}$$
As impedance decreases, the current increases.

Answer

is zero.

Answer

increases.

Answer

decreases.

Answer

remain constant.

AC fundamentals

When a capacitor is connected in series LR circuit, the alternating current flowing in the circuit

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