Question 20: AC fundamentals

Question

The ratio of the number of turns of the primary coil to the secondary coil of an ideal transformer is $5: 1$. The primary is connected to 220 V supply. What is the output power of the transformer if the output resistance is $11 \Omega$ ?

Accepted Answer

HereÃ¢ÂÂs how to work it out step by step:
Turns ratio Ã¢ÂÂ voltage ratio
$$\frac{N_p}{N_s}=5:1\quad\Longrightarrow\quad V_s=\frac{N_s}{N_p}\,V_p=\frac{1}{5}	imes220=44	ext{ V}$$
Secondary current
$$I_s=\frac{V_s}{R_{m load}}=\frac{44}{11}=4	ext{ A}$$
Output power
$$P_{m out}=V_s	imes I_s=44	imes4=176	ext{ W}$$
So the correct answer is
176 W
(Option C).

Answer

1760 W

Answer

1100 W

Answer

176 W

Answer

100 W

AC fundamentals

The ratio of the number of turns of the primary coil to the secondary coil of an ideal transformer is 5: 1. The primary is connected to 220 V supply. What is the output power of the transformer if the output resistance is 11 \Omega ?

Choose the correct answer: