Question 213: AC fundamentals

Question

In LC circuit the inductance L = 40 mH and
capacitance C = 100 $$\mu $$F. If a voltage
V(t) = 10sin(314t) is applied to the circuit, the
current in the circuit is given as :

Accepted Answer

Z = x
C
Ã¢ÂÂ x
L
= $${1 \over {\omega C}} - \omega L$$
= $${1 \over {314 	imes 100 	imes {{10}^{ - 6}}}} - 314 	imes 40 	imes {10^{ - 3}}$$
= 19.28 $$\Omega $$
As V
m
= I
m
Z
$$ \Rightarrow $$ 10 = I
m
$$ 	imes $$ 19.28
$$ \Rightarrow $$ I
m
= $${{10} \over {19.28}}$$ = 0.52 A
$$ 	herefore $$ I = 0.52 sin(314t + $${\pi  \over 2}$$)
= 0.52 cos(314t)

Answer

0.52 cos 314 t

Answer

5.2 cos 314 t

Answer

0.52 sin 314 t

Answer

10 cos 314 t

AC fundamentals

In LC circuit the inductance L = 40 mH and capacitance C = 100 $\mu $F. If a voltage V(t) = 10sin(314t) is applied to the circuit, the current in the circuit is given as :

Choose the correct answer: