Question 164: AC fundamentals

Question

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes $$x$$ times its initial resonant frequency $$\omega_0$$. The value of $$x$$ is :

Accepted Answer

The resonance frequency of LC oscillations circuit is
$$
\begin{aligned}
& \omega_0=\frac{1}{\sqrt{\mathrm{LC}}} \\
& \mathrm{L} ightarrow 2 \mathrm{~L} \\
& \mathrm{C} ightarrow 8 \mathrm{C} \\
& \omega=\frac{1}{\sqrt{2 \mathrm{~L} 	imes 8 \mathrm{C}}}=\frac{1}{4 \sqrt{\mathrm{LC}}} \\
& \omega=\frac{\omega_0}{4}
\end{aligned}
$$
So $\mathrm{x}=\frac{1}{4}$

Answer

1/4

Answer

1/16

Answer

4

Answer

16

AC fundamentals

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes $x times its initial resonant frequency \omega_0. The value of x$ is :

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