Question 344: AC fundamentals

Question

Three inductances are connected as shown in figure. The equivalent inductance is

Accepted Answer

Equivalent inductance or inductances connected in parallel is $\mathrm{L}_{\mathrm{p}}=\frac{1}{\mathrm{~L}_1}+\frac{1}{\mathrm{~L}_2}$
$$	herefore \quad \mathrm{L}_{\mathrm{p}}=\frac{1}{\left(\frac{2}{\mathrm{~L}}+\frac{2}{\mathrm{~L}}ight)}=\frac{\mathrm{L}}{4}$$
Equivalent inductance in series
$$\begin{aligned}
\mathrm{L}_{\mathrm{s}} & =\mathrm{L}_{\mathrm{p}}+\mathrm{L}_3 \
& =\frac{\mathrm{L}}{4}+\frac{3}{4} \mathrm{~L}=\mathrm{L}
\end{aligned}$$

Answer

$\mathrm{\frac{L}{4}}$

Answer

$\frac{5}{4} \mathrm{~L}$

Answer

$\frac{7}{4} \mathrm{~L}$

Answer

$\mathrm{L}$

AC fundamentals

Three inductances are connected as shown in figure. The equivalent inductance is

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