Question 263: AC fundamentals

Question

In series LCR circuit C $=2 \mu \mathrm{~F}, \mathrm{~L}=5 \mathrm{mH}$ and $\mathrm{R}=5 \Omega$. The ratio of energy stored in the inductor to that in capacitor, when maximum current flows through the circuit is

Accepted Answer

Energy stored in capacitor is,
$$ \mathrm{U}=\frac{1}{2} \mathrm{CV}^2 $$
Similarly, energy stored in inductor $=\frac{1}{2} \mathrm{LI}^2$
$$ 	herefore \quad \frac{\mathrm{U}_{	ext {inductorl }}}{\mathrm{U}_{	ext {capacitor }}}=\frac{\frac{1}{2} \mathrm{LI}^2}{\frac{1}{2} \mathrm{CV}^2}=\frac{\mathrm{L}}{\mathrm{C}} 	imes \frac{1}{\mathrm{R}^2}=\frac{5 	imes 10^{-3}}{2 	imes 10^{-6}} 	imes \frac{1}{5^2}=\frac{100}{1} $$

Answer

$200: 1$

Answer

$100: 1$

Answer

$300: 1$

Answer

$500: 1$

AC fundamentals

In series LCR circuit C =2 \mu \mathrm{~F}, \mathrm{~L}=5 \mathrm{mH} and \mathrm{R}=5 \Omega. The ratio of energy stored in the inductor to that in capacitor, when maximum current flows through the circuit is

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