Question 149: EM waves

Question

Magnetic field in a plane electromagnetic wave is given by
$$\overrightarrow B $$ = B0 sin (k x + $$\omega $$t) $$\widehat j\,T$$ 
Expression for corresponding electric field will be :  
Where c is speed of light.

Accepted Answer

The relation between electric and magnetic field is ,
C = $${{\overrightarrow E } \over {\overrightarrow B }}$$
$$ \Rightarrow $$$$\,\,\,$$ $$\overrightarrow E $$ = C $$\overrightarrow B $$
Electric field component is perpendicular to the direction of magnetic field. Given magnetic field is along y $$-$$ axis,
So, electric field along z $$-$$ axis will be
$$\overrightarrow E $$ = B
0
C sin (kx + $$\omega $$t) $$\,\widehat k$$ v/m

Answer

$$\overrightarrow E $$ = B0 c sin (k x + $$\omega $$t) $$\widehat k$$ V/m

Answer

$$\overrightarrow E $$ = $${{{B_0}} \over c}$$ sin  (k x + $$\omega $$t) $$\widehat k$$ V/m

Answer

$$\overrightarrow E $$ = $$-$$ B0 c sin (kx +$$\omega $$t) $$\widehat k$$ V/m

Answer

$$\overrightarrow E $$ =  B0 c sin (kx $$-$$$$\omega $$t) $$\widehat k$$ V/m

EM waves

Magnetic field in a plane electromagnetic wave is given by $\overrightarrow B = B0 sin (k x + \omega t) \widehat j\,T$ Expression for corresponding electric field will be : Where c is speed of light.

Choose the correct answer: