Question 131: EM waves

Question

The electric field of a plane electromagnetic
wave is given by
$$\overrightarrow E  = {E_0}\widehat i\cos (kz)cos(\omega t)$$ The corresponding magnetic field $$\overrightarrow B $$ is then given by

Accepted Answer

$$ 	herefore \overrightarrow E  	imes \overrightarrow B \parallel \overrightarrow v $$
Given that wave is propagating along positive z-axis and $$\overrightarrow E $$ along positive x-axis. Hence $$\overrightarrow B $$ along y-axis.
From Maxwell equation
$$\overrightarrow V  	imes \overrightarrow E  =  - {{\partial B} \over {\partial t}}$$
i.e. $${{\partial E} \over {\partial Z}} =  - {{\partial B} \over {dt}}$$ and $${B_0} = {{{E_0}} \over C}$$

Answer

$$\overrightarrow B  = {{{E_0}} \over C}\widehat j\sin (kz)\sin (\omega t)$$

Answer

$$\overrightarrow B  = {{{E_0}} \over C}\widehat j\sin (kz)\cos (\omega t)$$

Answer

$$\overrightarrow B  = {{{E_0}} \over C}\widehat j\cos (kz)\sin (\omega t)$$

Answer

$$\overrightarrow B  = {{{E_0}} \over C}\widehat k\sin (kz)\cos (\omega t)$$

EM waves

The electric field of a plane electromagnetic wave is given by $\overrightarrow E = {E_0}\widehat i\cos (kz)cos(\omega t) The corresponding magnetic field \overrightarrow B $ is then given by

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