Question 156: EM waves

Question

An electromagnetic wave in vacuum has the electric and magnetic field $$\mathop E\limits^ 	o  $$and $$\mathop B\limits^ 	o  $$, which are always perpendicular to each other. The direction of polarization is given by $$\mathop X\limits^ 	o  $$ and that of wave propagation by $$\mathop k\limits^ 	o  $$. Then

Accepted Answer

as The $$E.M.$$ wave are transverse in nature i.e.,
$$ = {{\overrightarrow k  	imes \overrightarrow E } \over {\mu \omega }} = \overrightarrow H \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( i ight)$$
where $$\overrightarrow H  = {{\overrightarrow B } \over \mu }$$
and $${{\overrightarrow k  	imes \overrightarrow H } \over {\omega \varepsilon }} =  - \overrightarrow E \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( {ii} ight)$$
$$\overrightarrow k $$ is $$ \bot \,\,\overrightarrow H $$ and $$\overrightarrow k $$ is also $$ \bot $$ to $$\overrightarrow E $$
or In other words $$\overrightarrow X ||\overrightarrow E $$ and $$\overrightarrow k ||\overrightarrow E  	imes \overrightarrow B $$

Answer

$$\mathop X\limits^ 	o  ||\mathop B\limits^ 	o  $$ and $$\mathop X\limits^ 	o  ||\mathop B\limits^ 	o   	imes \mathop E\limits^ 	o  $$

Answer

$$\mathop X\limits^ 	o  ||\mathop E\limits^ 	o  $$ and $$\mathop k\limits^ 	o  ||\mathop E\limits^ 	o   	imes \mathop B\limits^ 	o  $$

Answer

$$\mathop X\limits^ 	o  ||\mathop B\limits^ 	o  $$ and $$\mathop k\limits^ 	o  ||\mathop E\limits^ 	o   	imes \mathop B\limits^ 	o  $$

Answer

$$\mathop X\limits^ 	o  ||\mathop E\limits^ 	o  $$ and $$\mathop k\limits^ 	o  ||\mathop B\limits^ 	o   	imes \mathop E\limits^ 	o  $$

EM waves

An electromagnetic wave in vacuum has the electric and magnetic field $\mathop E\limits^ \to and \mathop B\limits^ \to , which are always perpendicular to each other. The direction of polarization is given by \mathop X\limits^ \to and that of wave propagation by \mathop k\limits^ \to $. Then

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