Question 78: EM waves

Question

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$$
$$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$$
Then the correct relation between E$$_0$$ and B$$_0$$ is given by

Accepted Answer

$E_{x}=E_{0} \sin (k z-\omega t)$
$B_{y}=B_{0} \sin (k z-\omega t)$
$\because$ Velocity $=\frac{E_{0}}{B_{0}}$
$\frac{\omega}{k}=\frac{E_{0}}{B_{0}}$
$\omega B_{0}=k E_{0}$

Answer

$$\mathrm{{E_o}{B_o} = \omega k}$$

Answer

$$\mathrm{{E_0} = k{B_0}}$$

Answer

$$\mathrm{k{E_0} = \omega {B_0}}$$

Answer

$$\mathrm{\omega {E_0} = k{B_0}}$$

EM waves

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by $\mathrm{{E_x} = {E_o}\sin (kz - \omega t)} \mathrm{{B_y} = {B_o}\sin (kz - \omega t)} Then the correct relation between E_0 and B_0$ is given by

Choose the correct answer: