Question 68: EM waves

Question

The energy density associated with electric field $$\vec{E}$$ and magnetic field $$\vec{B}$$ of an electromagnetic wave in free space is given by $$\left(\epsilon_{0}-\right.$$ permittivity of free space, $$\mu_{0}-$$ permeability of free space)

Accepted Answer

The energy density associated with the electric field $$\vec{E}$$ and magnetic field $$\vec{B}$$ of an electromagnetic wave in free space is given by:
For the electric field:
$$U_{E} = \frac{1}{2} \epsilon_{0} E^2$$
For the magnetic field:
$$U_{B} = \frac{1}{2} \frac{B^2}{\mu_{0}}$$
These expressions match Option A:
$$U_{E} = \frac{\epsilon
{0} E^{2}}{2}, U_{B} = \frac{B^{2}}{2 \mu
{0}}$$

Answer

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

Answer

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

Answer

$$U_{E}=\frac{\epsilon_{0} E^{2}}{2}, U_{B}=\frac{\mu_{0} B^{2}}{2}$$

Answer

$$U_{E}=\frac{E^{2}}{2 \epsilon_{0}}, U_{B}=\frac{B^{2}}{2 \mu_{0}}$$

EM waves

The energy density associated with electric field $\vec{E} and magnetic field \vec{B} of an electromagnetic wave in free space is given by \left(\epsilon_{0}-\right. permittivity of free space, \mu_{0}-$ permeability of free space)

Choose the correct answer: