Question 140: Waves Optics

Question

Visible light of wavelength 6000 $$ 	imes $$ 10-8 cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60o from the central maximum. If the first minimum is produced at $$	heta $$1, then $$	heta $$1, is close to :

Accepted Answer

For 2
nd
minima
$$\sin 	heta  = {{2\lambda } \over d }$$
$$ \Rightarrow $$ $$\sin 60^\circ  = {{2\lambda } \over d}$$
$$ \Rightarrow $$ $${\lambda  \over d} = {{\sqrt 3 } \over 4}$$
For 1
st
minima
$$\sin {	heta _1} = {\lambda  \over d}$$ = $${{\sqrt 3 } \over 4}$$
$$ \Rightarrow $$ $${	heta _1} = $$ 25
o

Answer

45o

Answer

30o

Answer

25o

Answer

20o

Waves Optics

Visible light of wavelength 6000 $ \times 10-8 cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60o from the central maximum. If the first minimum is produced at \theta 1, then \theta $1, is close to :

Choose the correct answer: