Question 276: Waves Optics

Question

In a double slit experiment, the distance between slits is increased 10 times, whereas their distance from screen is halved, the fringe width

Accepted Answer

In a double-slit experiment, the fringe width is determined by the formula:
$ \beta = \frac{D \lambda}{d} $
where $\beta$ is the fringe width, $D$ is the distance from the slits to the screen, $\lambda$ is the wavelength of light, and $d$ is the distance between the slits.
If the distance between the slits, $d$, is increased by 10 times and the distance from the slits to the screen, $D$, is halved, then the new fringe width, $\beta_2$, can be calculated as follows:
$ \beta_2 = \frac{\frac{D}{2} \lambda}{10d} = \frac{D \lambda}{20d} $
Therefore, $\beta_2$ becomes $\frac{1}{20}$ of the original fringe width $\beta_1$.

Answer

remain the same.

Answer

becomes $\frac{1}{10}$ times.

Answer

becomes $\frac{1}{20}$ times.

Answer

becomes $\frac{1}{90}$ times.

Waves Optics

In a double slit experiment, the distance between slits is increased 10 times, whereas their distance from screen is halved, the fringe width

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