Question 428: Waves Optics

Question

In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width

Accepted Answer

Fringe width, $$\beta $$ = $${{\lambda D} \over d}$$
From question D' = 2D and d' = $${d \over 2}$$
$$ 	herefore $$ $$\beta $$' = $${{\lambda D'} \over {d'}}$$ = 4$$\beta $$

Answer

is halved

Answer

becomes four times

Answer

remains unchanged

Answer

is doubled

Waves Optics

In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width

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