Question 392: Waves Optics

Question

Light of wavelength ' $\lambda$ ' is incident on a single slit of width ' $a$ ' and the distance between slit and screen is ' $D$ '. In diffraction pattern, if slit width is equal to the width of the central maximum then ' $D$ ' is equal to

Accepted Answer

The diffraction pattern due to a single slit is shown below
The width of central maximum is given by
$$2 y=\frac{2 D \lambda}{a}\quad	ext{.... (i)}$$
where, $\lambda=$ wavelength of incident light.
Here, $a=2 y$, then from Eq. (i), we get
$$a=\frac{2 D \lambda}{a} \Rightarrow D=\frac{a^2}{2 \lambda}$$

Answer

$\frac{a}{2 \lambda}$

Answer

$\frac{a^2}{2 \lambda}$

Answer

$\frac{a}{\lambda}$

Answer

$\frac{a^2}{\lambda}$

Waves Optics

Light of wavelength ' \lambda ' is incident on a single slit of width ' a ' and the distance between slit and screen is ' D '. In diffraction pattern, if slit width is equal to the width of the central maximum then ' D ' is equal to

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