Question 77: Waves Optics

Question

Two polarisers $P_1$ and $P_2$ are placed in such a way that the intensity of the transmitted light will be zero. A third polariser $P_3$ is inserted in between $P_1$ and $P_2$, at particular angle between $P_2$ and $P_3$. The transmitted intensity of the light passing the through all three polarisers is maximum. The angle between the polarisers $P_2$ and $P_3$ is :

Accepted Answer

Through $P_2 I_1=I_0 \sin ^2\left(\frac{\pi}{2}-	hetaight)$
$$I_1=I_0 \cos ^2 	heta$$
Through $P_3 I_{	ext {net }}=\left(I_0 \cos ^2 	hetaight) \sin ^2 	heta$
$$I_{	ext {net }}=\frac{I_0}{4}[\sin (2 	heta)]^2 	ext { for max } I_{	ext {net }} 	heta=45^{\circ}$$
So angle between $\mathrm{P}_2$ and $\mathrm{P}_3=\frac{\pi}{4}$
Correct Ans. (1)

Answer

$\pi / 6$

Answer

$\frac{\pi}{3}$

Answer

$\frac{\pi}{4}$

Answer

$\pi / 8$

Waves Optics

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