Question 414: Waves Optics

Question

The ratio of resolving powers of an optical microscope for two wavelength $$\lambda $$1 = 4000 $$\mathop A\limits^ \circ  $$ and $${\lambda _2}$$ = 6000 $$\mathop A\limits^ \circ  $$ is

Accepted Answer

The resolving power of an optical microscope,
RP = $${{2\mu \sin 	heta } \over \lambda }$$
$$ \Rightarrow $$ RP $$ \propto $$ $${1 \over \lambda }$$
Now, $${{R{P_1}} \over {R{P_2}}} = {{{\lambda _2}} \over {{\lambda _1}}}$$
= $${{6000} \over {4000}}$$ = $${3 \over 2}$$

Answer

9 : 4

Answer

3 : 2

Answer

16 : 81

Answer

8 : 27

Waves Optics

The ratio of resolving powers of an optical microscope for two wavelength $\lambda 1 = 4000 \mathop A\limits^ \circ and {\lambda _2} = 6000 \mathop A\limits^ \circ $ is

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