Question 319: Waves Optics

Question

Two wavelengths of sodium light $$590 \mathrm{~nm}$$ and $$596 \mathrm{~nm}$$ are used one after another to study diffraction due to single slit of aperture $$2 	imes 10^{-6} \mathrm{~m}$$. The distance between the slit and the screen is $$1.5 \mathrm{~m}$$. The separation between the positions of first maximum of the diffraction pattern obtained in the two cases is

Accepted Answer

First maximum in single slit diffraction pattern is obtained at, $$x=\frac{3 \lambda D}{2 d}$$
$$\begin{array}{ll}
	herefore & \Delta \mathrm{x}=\frac{3 \mathrm{D} 	imes \Delta \lambda}{2 \mathrm{~d}}=\frac{3 	imes 1.5}{2 	imes 2 	imes 10^{-6}}(596-590) \
	herefore & \Delta \mathrm{x}=6.75 \mathrm{~mm}
\end{array}$$

Answer

5.5 mm

Answer

5.75 mm

Answer

6.25 mm

Answer

6.75 mm

Waves Optics

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