Question 265: Dual Nature of Matter and Radiation

Question

If the frequency of incident light in a photoelectric experiment is doubled, then stopping potential will

Accepted Answer

By photoelectric effect,
$$ \mathrm{eV}_0=\mathrm{h} v-\phi $$
$	herefore \quad \mathrm{V}_0=\frac{\mathrm{h} v-\phi}{\mathrm{e}} \ldots\left(\mathrm{V}_0=ight.$ initial stopping potential)
Initial frequency $(v)$ is doubled.
$$ \begin{aligned} &\begin{aligned} 	herefore\,\, &  V_0^{\prime}=\frac{h(2 v)-\phi_0}{e} \ldots\left(V_0^{\prime}=	ext { New stopping potential }ight) \ & V_0^{\prime}=\frac{2 h v-\phi_0}{e} \ & V_0^{\prime}=2 \cdot \frac{h v-\phi}{e}+\frac{\phi}{e}=2 V_0+\frac{\phi}{e} \ 	herefore\,\, & V_0^{\prime}>2 V_0 \end{aligned}\ 	herefore &	ext { Stopping potential becomes more than double. } \end{aligned} $$

Answer

be doubled.

Answer

be halved.

Answer

become more than double.

Answer

become less than double.

Dual Nature of Matter and Radiation

If the frequency of incident light in a photoelectric experiment is doubled, then stopping potential will

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