Question 146: Dual Nature of Matter and Radiation

Question

An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are Ee and pe and that of photon are Eph and pph respectively. Which of the following is correct?

Accepted Answer

$$\lambda  = {h \over p} \Rightarrow p = {h \over \lambda }$$
Now, A/Q, $${h \over {{P_e}}} = {h \over {{P_{photon}}}}$$
$$ \Rightarrow {P_e} = {P_{photon}}$$ ....... (i)
Now, $${K_e} = {1 \over 2}M{v^2} = {{Pv} \over 2}$$
$${K_{ph}} = m{c^2} = Pc$$ ..... (ii)
$${{{K_e}} \over {{K_{eq}}}} = {v \over {2c}}$$

Answer

$${{{E_e}} \over {{E_{ph}}}} = {{2c} \over v}$$

Answer

$${{{E_e}} \over {{E_{ph}}}} = {v \over {2c}}$$

Answer

$${{{p_e}} \over {{p_{ph}}}} = {{2c} \over v}$$

Answer

$${{{p_e}} \over {{p_{ph}}}} = {v \over {2c}}$$

Dual Nature of Matter and Radiation

An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are Ee and pe and that of photon are Eph and pph respectively. Which of the following is correct?

Choose the correct answer: