Question 346: Dual Nature of Matter and Radiation

Question

In a photoelectric experiment, a graph of maximum kinetic energy $$(\mathrm{KE}_{	ext {max }})$$ against the frequency of incident radiation (v) is plotted. If $$\mathrm{A}$$ and $$\mathrm{B}$$ are the intercepts on the $$\mathrm{X}$$ and $$\mathrm{Y}$$ axis respectively then the Planck's constant is given by

Accepted Answer

Kinetic energy is given by
$$	ext { (K.E. })_{\max }=\mathrm{h} v-\mathrm{h} v_0$$
Comparing $$y=m x+c$$
We get $$x$$-intercept when
$$	ext { (K.E. })_{\max }=0 	ext {, i.e. } \mathrm{h} v-\mathrm{h} v_0=0$$
or $$v=v_0=A$$
We get $$y$$-intercept when $$v=0$$
$$\begin{aligned}
& 	herefore 	ext { (K.E. })_{\max }=-\mathrm{h} v_0=\mathrm{B} \
& 	herefore\left|\frac{\mathrm{B}}{\mathrm{A}}ight|=\frac{\mathrm{h} v_0}{v_0}=\mathrm{h}
\end{aligned}$$

Answer

$$\mathrm{A}+\mathrm{B}$$

Answer

$$\frac{B}{A^{\prime}}$$

Answer

$$\mathrm{A} 	imes \mathrm{B}$$

Answer

$$\frac{\mathrm{A}}{\mathrm{B}}$$

Dual Nature of Matter and Radiation

In a photoelectric experiment, a graph of maximum kinetic energy $(\mathrm{KE}_{\text {max }}) against the frequency of incident radiation (v) is plotted. If \mathrm{A} and \mathrm{B} are the intercepts on the \mathrm{X} and \mathrm{Y}$ axis respectively then the Planck's constant is given by

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