Question 338: Dual Nature of Matter and Radiation

Question

The maximum kinetic energy of the photoelectrons varies

Accepted Answer

For electron, de Broglie wavelength, $$\lambda=\frac{1.228}{\sqrt{V}}$$
Given: $$\lambda_2=\lambda_1+0.5 \lambda_1=1.5 \lambda_1$$
$$\begin{array}{ll}
	herefore \quad & \frac{\lambda_2}{\lambda_1}=\sqrt{\frac{V_1}{V_2}} \
& \Rightarrow \frac{V_1}{V_2}=\left(\frac{\lambda_2}{\lambda_1}ight)^2=\left(\frac{1.5 \lambda_1}{\lambda_1}ight)^2=\left(\frac{3}{2}ight)^2=\frac{9}{4}
\end{array}$$

Answer

inversely with the intensity of incident radiation and is independent of its frequency.

Answer

inversely with the frequency of incident radiation and is independent on its intensity.

Answer

linearly with the frequency of incident radiation and depends on its intensity

Answer

linearly with the frequency of incident radiation and is independent of its intensity.

Dual Nature of Matter and Radiation

The maximum kinetic energy of the photoelectrons varies

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