Question 111: Dual Nature of Matter and Radiation

Question

The variation of stopping potential $$\left(\mathrm{V}_{0}\right)$$ as a function of the frequency $$(v)$$ of the incident light for a metal is shown in figure. The work function of the surface is

Accepted Answer

$$
\begin{aligned}
& e V_0=\frac{h c}{\lambda}-\phi \\
& V_0=\frac{h c}{e \lambda}-\left(\frac{\phi}{e}ight)=\frac{h v}{e}-\left(\frac{\phi}{e}ight)
\end{aligned}
$$
When $V_0=0$,
$$
\begin{aligned}
\frac{\phi}{e} & =\left(\frac{h v}{e}ight) \\
\phi & =h v=\frac{6.626 	imes 10^{-34} 	imes 5 	imes 10^{14}}{1.6 	imes 10^{-19}} \\
& =\frac{6.626 	imes 5}{1.6} 	imes 10^{-1} \\
& =\frac{6.626 	imes 5}{16} \approx 2.07 \mathrm{eV}
\end{aligned}
$$

Answer

1.36 eV

Answer

18.6 eV

Answer

2.98 eV

Answer

2.07 eV

Dual Nature of Matter and Radiation

The variation of stopping potential $\left(\mathrm{V}_{0}\right) as a function of the frequency (v)$ of the incident light for a metal is shown in figure. The work function of the surface is

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