Question 325: Dual Nature of Matter and Radiation

Question

The de-Broglie wavelength $$(\lambda)$$ of a particle is related to its kinetic energy (E) as

Accepted Answer

De-Broglie wavelength, $$\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}}$$
$$	herefore \quad \lambda \propto \mathrm{E}^{-\frac{1}{2}}$$

Answer

$$\lambda \propto \mathrm{E}$$

Answer

$$\lambda \propto \mathrm{E}^{-1}$$

Answer

$$\lambda \propto \mathrm{E}^{\frac{1}{2}}$$

Answer

$$\lambda \propto \mathrm{E}^{-\frac{1}{2}}$$

Dual Nature of Matter and Radiation