Question 370: Dual Nature of Matter and Radiation

Question

The light of wavelength $$\lambda$$ incident on the surface of metal having work function $$\phi$$ emits the electrons. The maximum velocity of electrons emitted is [ $$c=$$ velocity of light, $$h=$$ Planck's constant, $$m=$$ mass of electron]

Accepted Answer

photoelectric effect, the maximum kinetic energy possessed by the particle,
$$\begin{aligned}
\mathrm{KE}_{\max } & =h v-\phi \
\frac{1}{2} m v^2 & =\frac{h c}{\lambda}-\phi \quad \left(\because v=\frac{c}{\lambda}ight)\
\Rightarrow \quad v^2 & =\frac{2(h c-\phi \lambda)}{\lambda m} \
v & =\left[\frac{2(h c-\lambda \phi)}{m \lambda}ight]^{1 / 2}
\end{aligned}$$

Answer

$$\left[\frac{2(h v-\phi) \lambda}{m c}\right]$$

Answer

$$\left[\frac{2(h c-\lambda \phi)}{m \lambda}\right]^{1 / 2}$$

Answer

$$\left[\frac{2(h c-\lambda)}{m \lambda}\right]^{1 / 2}$$

Answer

$$\left[\frac{2(h c-\phi)}{m \lambda}\right]$$

Dual Nature of Matter and Radiation

The light of wavelength $\lambda incident on the surface of metal having work function \phi emits the electrons. The maximum velocity of electrons emitted is [ c= velocity of light, h= Planck's constant, m=$ mass of electron]

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