Question 361: Dual Nature of Matter and Radiation

Question

A proton and alpha particle are accelerated through the same potential difference. The ratio of the de-Broglie wavelength of proton to that of alpha particle will be (mass of alpha particle is four times mass of proton.)

Accepted Answer

De-Broglie wavelength is given by
$$\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mqv}}}$$
If $$\lambda_1$$ and $$\lambda_2$$ are de-Broglie wavelengths of proton and alpha particle then
$$\frac{\lambda_1}{\lambda_2}=\sqrt{\frac{m_2 q_2}{m_1 q_1}}=\sqrt{4 	imes 2}=\sqrt{8}=2 \sqrt{2}$$

Answer

$$1: 2$$

Answer

$$2 \sqrt{2}: 1$$

Answer

$$1: 1$$

Answer

$$2: 1$$

Dual Nature of Matter and Radiation

A proton and alpha particle are accelerated through the same potential difference. The ratio of the de-Broglie wavelength of proton to that of alpha particle will be (mass of alpha particle is four times mass of proton.)

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