Question 128: Dual Nature of Matter and Radiation

Question

An $$\alpha$$-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:

Accepted Answer

$\lambda=\frac{h}{m v}=\frac{h}{\sqrt{2 m k}}$
So, $\lambda \propto \frac{1}{\sqrt{m}}$
So, $\lambda_{e}>\lambda_{p}>\lambda_{\alpha}$

Answer

$${\lambda _\alpha } > {\lambda _p} < {\lambda _e}$$

Answer

$${\lambda _\alpha } > {\lambda _p} > {\lambda _e}$$

Answer

$${\lambda _\alpha } = {\lambda _p} = {\lambda _e}$$

Answer

$${\lambda _\alpha } < {\lambda _p} < {\lambda _e}$$

Dual Nature of Matter and Radiation

An $\alpha$-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:

Choose the correct answer: