Question 4: Dual Nature of Matter and Radiation

Question

The stopping potential (V0) versus frequency $$
u $$ of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is

Accepted Answer

$$e{V_0} = h(
u  - {
u _0}) = h
u  - h{
u _0}$$
$${V_0} = \left( {{h \over e}} ight)
u  - \left( {{h \over e}} ight){
u _0}$$ ..... (i)
From Eq. (i), it follows that the slope of the graph is $${h \over e}$$.
Therefore,
h = e $$	imes$$ slope = 1.6 $$	imes$$ 10
$$-$$19
$$	imes$$ $${{16.5 - 0} \over {(8 - 4) 	imes {{10}^{15}}}}$$
$$ = {{1.6 	imes {{10}^{ - 19}} 	imes 16.5} \over {4 	imes {{10}^{ - 5}}}} = 6.6 	imes {10^{ - 34}}$$ J-s.

Answer

6.60 $$	imes$$ 10$$-$$34 J-s

Answer

6.69 $$	imes$$ 10$$-$$34 J-s

Answer

6.62 $$	imes$$ 10$$-$$34 J-s

Answer

6.63 $$	imes$$ 10$$-$$34 J-s

Dual Nature of Matter and Radiation

The stopping potential (V0) versus frequency $\nu $ of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is

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