Question 13: Atoms & Nuclei

Question

The total energy of an electron in the second excited state of hydrogen atom is about $$-1.51 \mathrm{~eV}$$. Its kinetic energy in this state is

Accepted Answer

Potential energy of an electron
$$(U)=-2 	ext { (kinetic Energy K) }$$
So, total energy, $$E=U+K=-2 K+K$$
$$\begin{aligned}
E & =-K \
\Rightarrow K & =-E \Rightarrow K=-(-1.51 \mathrm{~eV})=1.51 \mathrm{~eV}
\end{aligned}$$

Answer

$$-1.5 \mathrm{~eV}$$

Answer

$$-3.02 \mathrm{~eV}$$

Answer

3.02 eV

Answer

1.51 eV

Atoms & Nuclei

The total energy of an electron in the second excited state of hydrogen atom is about $-1.51 \mathrm{~eV}$. Its kinetic energy in this state is

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