Question 510: Atoms & Nuclei

Question

'$$\lambda_1$$' is the wavelength of series limit of Lyman series, '$$\lambda_2$$' is the wavelength of the first line line of Lyman series and '$$\lambda_3$$' is the series limit of the Balmer series. Then the relation between $$\lambda_1, \lambda_2$$ and $$\lambda_3$$ is

Accepted Answer

Series limit of Lyman series is given by
$$\frac{1}{\lambda_1}=\mathrm{R}\left(\frac{1}{1}-\frac{1}{\infty}ight)=\mathrm{R}$$
Series limit of Balmer series is given by
$$\frac{1}{\lambda_3}=\mathrm{R}\left(\frac{1}{4}-\frac{1}{\infty}ight)=\frac{\mathrm{R}}{4}$$
First line of Lyman series is given by
$$\begin{aligned}
& \frac{1}{\lambda_2}=\mathrm{R}\left(\frac{1}{1}-\frac{1}{4}ight)=\mathrm{R}-\frac{\mathrm{R}}{4}=\frac{1}{\lambda_1}-\frac{1}{\lambda_3} \
	herefore & \frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}
\end{aligned}$$

Answer

$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$

Answer

$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$

Answer

$$\lambda_2=\lambda_1+\lambda_3$$

Answer

$$\lambda_1=\lambda_2+\lambda_3$$

Atoms & Nuclei

'$\lambda_1' is the wavelength of series limit of Lyman series, '\lambda_2' is the wavelength of the first line line of Lyman series and '\lambda_3' is the series limit of the Balmer series. Then the relation between \lambda_1, \lambda_2 and \lambda_3$ is

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