Question 342: Atoms & Nuclei

Question

If the binding energy of the electron in a hydrogen atom is $$13.6eV,$$ the energy required to remove the electron from the first excited state of $$L{i^{ +  + }}$$ is

Accepted Answer

$${E_n} =  - {{13.6} \over {{n^2}}}{Z^2}eV/$$atom
For lithium ion $$Z=3;$$ $$n=2$$ (for first excited state)
$${E_n} =  - {{13.6} \over {{2^2}}} 	imes {3^2} =  - 30.6eV$$

Answer

$$30.6$$ $$eV$$

Answer

$$13.6$$ $$eV$$

Answer

$$3.4$$ $$eV$$

Answer

$$122.4$$ $$eV$$

Atoms & Nuclei

If the binding energy of the electron in a hydrogen atom is $13.6eV, the energy required to remove the electron from the first excited state of L{i^{ + + }}$ is

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