Question 174: Atoms & Nuclei

Question

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th excited state of a hydrogen atom is :

Accepted Answer

$$\frac{1}{2}|P E|=K E$$ for each value of $$\mathrm{n}$$ (orbit)
$$	herefore \frac{K E}{|P E|}=\frac{1}{2}$$

Answer

4

Answer

1

Answer

$$\frac{1}{2}$$

Answer

$$\frac{1}{4}$$

Atoms & Nuclei