Question 467: Atoms & Nuclei

Question

In the third orbit of hydrogen atom the energy of an electron ' $E$ '. In the fifth orbit of helium $(Z=2)$ the energy of an electron will be

Accepted Answer

$$\begin{aligned}
& E \propto \frac{Z^2}{n^2} \
& 	herefore \quad \frac{\mathrm{E}_{\mathrm{H}}}{\mathrm{E}_{\mathrm{Hc}}}=\frac{\left(\mathrm{Z}^2ight)_{\mathrm{H}}}{(\mathrm{n})_{\mathrm{H}}^2} 	imes \frac{(\mathrm{n})_{\mathrm{He}}^2}{\left(\mathrm{Z}^2ight)_{\mathrm{He}}} \
& =\frac{1}{3^2} 	imes \frac{5^2}{2^2}=\frac{25}{36} \
& 	herefore \quad \mathrm{E}_{\mathrm{He}}=\frac{36}{25} \mathrm{E}_{\mathrm{H}}=\frac{36}{25} \mathrm{E}
\end{aligned}$$

Answer

$\frac{25 \mathrm{E}}{36}$

Answer

$\frac{36 \mathrm{E}}{25}$

Answer

$\frac{3 \mathrm{E}}{5}$

Answer

$\frac{5 \mathrm{E}}{3}$

Atoms & Nuclei

In the third orbit of hydrogen atom the energy of an electron ' E '. In the fifth orbit of helium (Z=2) the energy of an electron will be

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