Question 596: Atoms & Nuclei

Question

The decay constant of a radio isotope is $$\lambda $$. If A1 and A2 are its activities at times t1 and t2 respectively, the number of nuclei which have decayed during the time (t1 $$-$$ t2)

Accepted Answer

A
1
= $$\lambda $$N
1
at time t
1
A
2
= $$\lambda $$N
2
at time t
2
Therefore, number of nuclei decayed during time
interval (t
1
Ã¢ÂÂ t
2
) is
N
1
- N
2
= $${{\left[ {{A_1} - {A_2}} \right]} \over \lambda }$$

Answer

A1t1 $$-$$ A2t2

Answer

A1 $$-$$ A2

Answer

(A1 $$-$$ A2)/$$\lambda $$

Answer

$$\lambda ({A_1} - {A_2})$$

Atoms & Nuclei

The decay constant of a radio isotope is $\lambda . If A1 and A2 are its activities at times t1 and t2 respectively, the number of nuclei which have decayed during the time (t1 -$ t2)

Choose the correct answer: