Question 549: Atoms & Nuclei

Question

In the given nuclear reaction, the element X is
$${}_{11}^{22}Na 	o X + {e^ + } + v$$

Accepted Answer

The nuclear reaction is given as
$${}_{11}^{22}Na 	o {}_Z^AX + {}_{ + 1}{e^0} + v$$
From conservation of atomic number
$$11 = Z + 1 \Rightarrow Z = 10 \Rightarrow Ne$$
From conservation of mass number
$$22 = A + 0 \Rightarrow A = 22$$
$$	herefore$$ $${}_Z^AX = {}_{10}^{22}Ne$$

Answer

$${}_{11}^{23}Na$$

Answer

$${}_{10}^{23}Ne$$

Answer

$${}_{10}^{22}Ne$$

Answer

$${}_{12}^{22}Mg$$

Atoms & Nuclei

In the given nuclear reaction, the element X is ${}_{11}^{22}Na \to X + {e^ + } + v

Choose the correct answer: