Question 394: Atoms & Nuclei

Question

A hydrogen atom in its first excited state absorbs a photon of energy x $$	imes$$ 10$$-$$2 eV and excited to a higher energy state where the potential energy of electron is $$-$$1.08 eV. The value of x is ______________.

Accepted Answer

As, $E_{n}=\frac{P \cdot E_{n}}{2}=-\frac{1.08}{2}=-0.544$
$$
\begin{aligned}
& 	ext { So, } \Delta \mathrm{E}, \mathrm{E}_{\mathrm{f}}-\mathrm{E}_{\mathrm{i}}=-0.544-\left(-\frac{13.6}{2^{2}}ight)=3.4-0.544 \\
& \approx 2.86 \mathrm{eV}=286 	imes 10^{-2} \mathrm{eV}
\end{aligned}
$$

Atoms & Nuclei

A hydrogen atom in its first excited state absorbs a photon of energy x $\times 10-2 eV and excited to a higher energy state where the potential energy of electron is -$1.08 eV. The value of x is ______________.

Choose the correct answer: