Question 493: Atoms & Nuclei

Question

If an electron in a hydrogen atom jumps from an orbit of level $$n=3$$ to orbit of level $$n=2$$, then the emitted radiation frequency is (where R = Rydberg's constant, C = Velocity of light)

Accepted Answer

$$\begin{array}{ll} 
& \frac{1}{\lambda}=\mathrm{R}\left[\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}ight] \
	herefore \quad & \frac{1}{\lambda}=\left[\frac{1}{2^2}-\frac{1}{3^2}ight]=\frac{5}{36} \mathrm{R} \
	herefore \quad & \mathrm{f}=\frac{\mathrm{c}}{\lambda}=\frac{5}{36} \mathrm{Rc}
\end{array}$$

Answer

$$\frac{3 \mathrm{RC}}{27}$$

Answer

$$\frac{\mathrm{RC}}{25}$$

Answer

$$\frac{8 \mathrm{RC}}{9}$$

Answer

$$\frac{5 \mathrm{RC}}{36}$$

Atoms & Nuclei

If an electron in a hydrogen atom jumps from an orbit of level $n=3 to orbit of level n=2$, then the emitted radiation frequency is (where R = Rydberg's constant, C = Velocity of light)

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