Question 660: Atoms & Nuclei

Question

A nuclide at rest emits an $\alpha$-particle. In this process

Accepted Answer

As $$f_{	ext {ext }}=0$$, Hence $$P_s=$$ constant
or $$\mathrm{P}_\alpha+\mathrm{P}_N=$$ constant
Because nuclide was at rest before emission of $$\alpha$$-particle, hence according to law of conservation of momentum,
$$P_\alpha+P_N=$$ constant - 1
Thus, $$\alpha$$-particle and the nucleus move in opposite directions. Further, as $$m_N \gg m_\alpha$$, hence, $$v_\alpha \gg v_N$$

Answer

$$\alpha$$-particle moves with large velocity and the nucleus remains at rest.

Answer

Both $$\alpha$$-particle and nucleus move with equal speed in opposite directions.

Answer

Both move in opposite directions except $$\alpha$$-particle with greater speed.

Answer

Both move in opposite direction with greater velocity of $$\alpha$$-particle.

Atoms & Nuclei

A nuclide at rest emits an \alpha-particle. In this process

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