Question 657: Atoms & Nuclei

Question

The activity of a radioactive sample is measured as No counts per minute at $$t=0$$ and $$\mathrm{N}_0 / \mathrm{e}$$ counts per minute at $$t=6 \mathrm{~min}$$. The time (in minutes) at which the activity reduces to half its value is.

Accepted Answer

$$N=N_0 e^{-\lambda t}$$
Here, $$t=6 \mathrm{mins}$$
$$\frac{N_0}{e}=N_0 e^{-6 \lambda}, 6 \lambda=1, \lambda=1 / 6$$
Now, $$T_{1 / 2}=\frac{\ln 2}{\lambda}=6 \ln 2$$

Answer

$$\left(\log _e 2\right) / 6$$

Answer

$$6 / \log _e 2$$

Answer

$$6 \log _0 2$$

Answer

$$6 \log _e 2$$

Atoms & Nuclei

The activity of a radioactive sample is measured as No counts per minute at $t=0 and \mathrm{N}_0 / \mathrm{e} counts per minute at t=6 \mathrm{~min}$. The time (in minutes) at which the activity reduces to half its value is.

Choose the correct answer: