Question 24: Atoms & Nuclei

Question

Radium having mass number 200 and binding energy per nucleon 5.6 MeV , splits into two fragments Cadmium of mass number 112 and Hassium of mass number 108. If the binding energy per nucleon for Cadmium and Hassium is approximately 8.0 MeV , then the energy $Q$ released per fission will be:

Accepted Answer

Total binding energy of the parent (Ra-200):
$$B_E(	ext{Ra}) = 200	imes5.6 = 1120	ext{ MeV}$$
Total binding energies of the two fragments:
Ã¢ÂÂ Cadmium-112:
$$B_E(	ext{Cd}) = 112	imes8.0 = 896	ext{ MeV}$$
Ã¢ÂÂ Hassium-108:
$$B_E(	ext{Hs}) = 108	imes8.0 = 864	ext{ MeV}$$
Sum of productsÃ¢ÂÂ binding energies:
$$896 + 864 = 1760	ext{ MeV}$$
Energy released (Q-value) is the gain in binding energy:
$$Q = B_E(	ext{products}) - B_E(	ext{parent})           = 1760 - 1120           = 640	ext{ MeV}$$
So the fission releases 640 MeV. ThatÃ¢ÂÂs option C.

Answer

598 MeV

Answer

176 MeV

Answer

640 MeV

Answer

475 MeV

Atoms & Nuclei

Radium having mass number 200 and binding energy per nucleon 5.6 MeV , splits into two fragments Cadmium of mass number 112 and Hassium of mass number 108. If the binding energy per nucleon for Cadmium and Hassium is approximately 8.0 MeV , then the energy Q released per fission will be:

Choose the correct answer: