Question 238: Atoms & Nuclei

Question

The half-life of $${}^{198}Au$$ is 3 days. If atomic weight of $${}^{198}Au$$ is 198 g/mol then the activity of 2 mg of $${}^{198}Au$$ is [in disintegration/second] :

Accepted Answer

A = $$\lambda$$N
$$\lambda  = {{\ln 2} \over {{t_{1/2}}}} = {{\ln 2} \over {3 	imes 24 	imes 60 	imes 60}}$$sec
$$-$$1
= 2.67 $$	imes$$ 10
$$-$$6
sec
$$-$$1
N = Number of atoms in 2 mg Au
$$ = {{2 	imes {{10}^{ - 3}}} \over {198}} 	imes 6 	imes {10^{23}}$$ = 6.06 $$	imes$$ 10
15
$$A = \lambda N = 1.618 	imes {10^{13}} = 16.18 	imes {10^{12}}$$ dps

Answer

2.67 $$	imes$$ 1012

Answer

6.06 $$	imes$$ 1018

Answer

32.36 $$	imes$$ 1012

Answer

16.18 $$	imes$$ 1012

Atoms & Nuclei

The half-life of ${}^{198}Au is 3 days. If atomic weight of {}^{198}Au is 198 g/mol then the activity of 2 mg of {}^{198}Au$ is [in disintegration/second] :

Choose the correct answer: