Question 585: Atoms & Nuclei

Question

If the nuclear radius of 27Al is 3.6 fermi, the approximate nuclear radius of 64Cu in fermi is

Accepted Answer

Nuclear radius, R = R
0
A
1/3
where R
0
is a constant and A is the mass number
$$ 	herefore $$ $${{{R_{Al}}} \over {{R_{Cu}}}} = {{{{\left( {27} ight)}^{1/3}}} \over {{{\left( {64} ight)}^{1/3}}}}$$ = $${3 \over 4}$$
$$ \Rightarrow $$ R
Cu
= $${4 \over 3} 	imes {R_{Al}}$$ = $${4 \over 3} 	imes 3.6$$ = 4.8 fermi

Answer

2.4

Answer

1.2

Answer

4.8

Answer

3.6

Atoms & Nuclei

If the nuclear radius of 27Al is 3.6 fermi, the approximate nuclear radius of 64Cu in fermi is

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